Truncating the triangular distribution

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    Rick Kossik

    Well, by forcing it to 0 it is no longer triangular. It would actually be a bit odd looking (some fraction centered on 0).  But on the other hand, what is so special about a triangular?  You say you "only have the 10th/90th".  What does that mean? How were those values estimated?  Where do those numbers come from?  On what basis are you assuming the distribution is triangular (or "truncated triangular", which is a bit odd)?  What do you actually think the shape of the distribution should be?  Can you draw it?

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